
Matrices
MATRICES
Top Terms

Then A is called the inverse of B and is denoted by B = A-1. If B is the inverse of A, then A is also the inverse of B.
Top Concepts
Hence, kA = [kaij] m × n
Given a matrix A = [aij]m × n, there will be a corresponding null matrix O of the same order such that A + O = O + A = A
A + (-A) = (-A) + A = O.
If A = [aij], B = [bij] are two matrices, and k and L are real number, then
In order to multiply two matrices A and B, the number of columns in A = number of rows in B.
Commutative law does not hold in matrices, whereas associative and distributive laws hold for matrix multiplication.
A(B + C) = AB + AC
(A + B)C = AC + BC
In general, the cancellation law is not applicable in matrix multiplication.
Laws of algebra are not applicable to matrices, i.e.
(A + B)2 ≠ A2 + 2AB + B2
and
(A + B) (A – B) ≠ A2 – B2
Top Formulae
Important Questions
Multiple Choice questions-
1. If A = [aij]m × n is a square matrix, if:
(a) m < n
(b) m > n
(c) m = n
(d) None of these.
2. Which of the given values of x and y make the following pair of matrices equal:
(a) x = – 13, y = 7
(b) Not possible to find
(c) y = 7, x = – 23
(d) x = – 13, y = – 23
3. The number of all possible matrices of order 3 × 3 with each entry 0 or 1 is
(a) 27
(b) 18
(c) 81
(d) 512.
Assume X, Y, Z, W and P are matrices of order 2 × n, 3 × 1, 2 × p, n × 3 and p × k respectively. Now answer the following (4-5):
4. The restrictions on n, k and p so that PY + WY will be defined are
(a) k = 3, p = n
(b) k is arbitrary, p = 2
(c) p is arbitrary
(d) k = 2,p = 3.
5. If n =p, then the order of the matrix 7X – 5Z is:
(a) p × 2
(b) 2 × n
(c) n × 3
(d) p × n.
6. If A, B are symmetric matrices of same order, then AB – BA is a
(a) Skew-symmetric matrix
(b) Symmetric matrix
(c) Zero matrix
(d) Identity matrix.
7.
(a) π6
(b) π3
(c) π
(d) 3π2
8. Matrices A and B will be inverse of each other only if:
(a) AB = BA
(b) AB – BA = O
(c) AB = O, BA = I
(d) AB = BA = I.
9.
(a) 1 + α² + ßγ = 0
(b) 1 – α² + ßγ = 0
(c) 1 – α² – ßγ = 0
(d) 1 + α² – ßγ = 0
10. If a matrix is both symmetric and skew- symmetric matrix, then:
(a) A is a diagonal matrix
(b) A is a zero matrix
(c) A is a square matrix
(d) None of these.
Very Short Questions:

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Long Questions:
Assertion and Reason Questions:
1. Two statements are given-one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer to these questions from thecodes(a), (b), (c) and (d) as given below.
Assertion(A):[1001]is an identity matrix.
Reason (R):A matrix A=[aij] is an identity matrix if .
2.Two statements are given-one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer to these questions from thecodes(a), (b), (c) and (d) as given below.
Assertion (A):Matrix⎡⎢⎣152⎤⎥⎦ is a column matrix.
Reason(R):A matrix of order m×1 is called a column matrix.
Case Study Questions:
1.Three shopkeepers A, B and C go to a store to buy stationary. A purchase 12 dozen notebooks, 5 dozen pens and 6 dozen pencils. B purchases 10 dozen notebooks, 6 dozen pens and 7 dozen pencils. C purchases 11 dozen notebooks, 13 dozen pens and 8 dozen pencils. A notebook costs ₹ 40, a pen costs ₹ 12 and a pencil costs ₹ 3.
Based on the above information, answer the following questions.
2.Consider 2 families A and B. Suppose there are 4 men,4 women and 4 children in family A and 2 men, 2 women and 2 children in family B. The recommend daily amount of calories is 2400 for a man, 1900 for a woman, 1800 for a children and 45 grams of proteins for a man, 55 grams for a woman and 33 grams for children.
Based on the above information, answer the following questions.

Answer Key-
Multiple Choice questions-
Very Short Answer:
(i) a33 = 9, a12 = 4
(ii) 3 × 3
Short Answer:
Here, 2A – 3B + 5C = 0
⇒ 2A = 3B – 5C
We have:
⇒ 2x + 3 = 9 …………. (1)
2z – 3 = 15 …………. (2)
2y = 12 …………. (3)
2t + 6 = 18 …………. (4)
From (1), ⇒ 2x = 9 – 3
⇒ 2x = 6
⇒ x = 3.
From (3) 2y = 12
⇒ y = 6.
From (2), ⇒ 2z – 3 = 15
⇒ 2z = 18
⇒ z = 9.
From (4), 2t + 6 = 18
⇒ 2t = 12
⇒ t = 6.
Hence, x = 3,y = 6, z = 9 and t = 6.
⇒ 8 = 15 + k and 3 = 10 + k
⇒ k = -1 and k = -7.
Hence, k –(-7).
Since A and B are symmetric matrices,
∴ A’ = A and B’ = B …(1)
Now,(AB – BA)’= (AB)’ – (BA)’
= B’A’ – A’B’
= BA – AB [Using (1)]
= – (AB – BA).
Hence, AB – BA is a skew-symmetric matrix.
Long Answer:
We have
Comparing the corresponding elements of two given matrices, we get:
2a + b = 4 …(1)
a-2b = – 3 …(2)
5c-d = 11 …(3)
4c + 3d = 24 …(4)
Solving (1) and (2):
From (1),
b = 4 – 2a …(5)
Putting in (2), a – 2 (4 – 2a) = – 3
⇒ a – 8 + 4a = -3
⇒ 5a = 5
⇒ a = 1.
Putting in (5),
b = 4 – 2(1) = 4 – 2 = 2.
Solving (3) and (4):
From (3),
d = 5c- 11 …(6)
Putting in (4),
4c+ 3 (5c- 11) = 24
⇒ 4c + 15c – 33 = 24
⇒ 19c = 57
⇒ c = 3.
Putting in (6),
d = 5 (3) – 11 = 15 – 11 = 4.
Hence, a = 1, b = 2, c = 3 and d = 4.
Comparing:
9 = a11 + 1 – 1 = a12 + 2,
4 = 113 – 1, -2 = a21
1 = a22 + 4, and 3 = a23 + 9
a11 = 8, a12 = – 3,
a13 = 5, a21 = -2
a22 = – 3, and a23 = – 6.
Comparing:
8 + c11 = 0 ⇒ c11 = -8,
4 + C12 = 0 ⇒ C12 = -4,
– 2 + C21 = 0 ⇒ C21 = 2
4 + C22 = 0 ⇒ C22 =- 4,
4 + c31 = 0 ⇒ C31 = -4
and 4 + c32 = 0 ⇒ C32 = -4.
We have: 2A + 3X = 5B
⇒ 2A + 3X-2A = 5B-2A
⇒ 2A-2A + 3X = 5B-2A
⇒ (2A – 2A) + 3X = 5B – 2A
⇒ O + 3X = 5B – 2A
[ ∵– 2A is the inverse of2A]
⇒ 3X = 5B – 2A.
[ ∵ O is the additive identity]
Hence, X = 13(5B – 2A)
Assertion and Reason Answers:
1.(d) A is false and R is true.
Solution:
We know that, is an indentity matrix
∴Given Assertion [A] is false We know that for identity matrix aij=1,ifi=jand aij=0,ifi≠j
∴Given Reason (R) is true Hence option (d) is the correct answer.
2. a) Both A and R are true and R is the correct explanation of A.
Solution:
We know that order of column matrix is always m×1
is column matrix.
⇒Assertion (A) is true Also Reason (R) is true and is correct explanation of A. Hence option (a) is the correct answer.
Case Study Answers:
1. Answer :
Solution:
Bill of A is ₹ 6696.
Solution:
(A + I)2 = A2 + 2A + I = 3A + I
⇒ (A + 1)3 = (3A + I) (A + I)
= 3A2 + 4A + I = 7A + I
∴∴ (A + I)3 – 7A = I
Solution:
A2 – B2 = (A – B) (A + B) = A2 + AB – BA – B2
∴∴ AB = BA
2. Answer :