
Determinants
DETERMINANTS
Top Definitions
f : M → K is defined by f(A) = k, where A ∈ M set of square matrices and k ∈ K set of numbers (real or complex).
Aij = (-1)i+jMij, where Mij is the minor of aij.
Notations to evaluate determinants:
Top Concepts
Then matrix X = A-1 B gives the unique solution of the system of equations if |A| is non-zero and A-1 exists.
Top Formulae
adj(AB) = (adj B)(adj A) .
Important Questions
Multiple Choice questions-
1. If , then x is equal to
(a) 6
(b) ±6
(c) -6
(d) 6, 6
2. Let A be a square matrix of order 3 × 3. Then |kA| is equal to
(a) k |A|
(b) k²|A|
(c) k³|A|
(d) 3k|A|
3. Which of the following is correct?
(a) Determinant is a square matrix
(b) Determinant is a number associated to a matrix
(c) Determinant is a number associated to a square matrix
(d) None of these.
4. If area of triangle is 35 sq. units with vertices (2, -6), (5, 4) and (k, 4). Then k is
(a) 12
(b) -2
(c) -12, -2
(d) 12, -2.
5. If and Aij is co-factors of aij, then A is given by
(a) a11A31 + a12A32 + a13A33
(b) a11A11 + a12A21 + a13A33
(c) a21A11 + a22A12 + a23A13
(d) a11A11 + a21A21 + a31A31
6. Let A be a non-singular matrix of order 3 × 3. Then |adj. A| is equal to
(a) |A|
(b) |A|²
(c) |A|³
(d) 3|A|
7. If A is any square matrix of order 3 x 3 such that |a| = 3, then the value of |adj. A| is?
(a) 3
(b) 13
(c) 9
(d) 27
8. If A is an invertible matrix of order 2, then det (A-1) is equal to
(a) det (A)
(b) 1det (A)
(c) 1
(d) 0
9. If a, b, c are in A.P., then determinant
(a) 0
(b) 1
(c) x
(d) 2x
10. If x, y, z are non-zero real numbers, then the inverse of matrix A =
Very Short Questions:


(i) the minor of the element a23 (C.B.S.E. 2012)
(ii) the co-factor of the element a32. (C.B.S.E. 2012)


Long Questions:
Assertion and Reason Questions-
1. Two statements are given-one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer to these questions from the codes(a), (b), (c) and (d) as given below.
Assertion(A):Minor of element 6 in the matrix is 3.
Reason (R):Minor of an element aij of a matrix is the determinant obtained by deleting its ith
row.
2. Two statements are given-one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer to these questions from the codes(a), (b), (c) and (d) as given below.
Assertion (A):For two matrices A and B of order 3, |A|=3, |B|=−4, then |2AB| is −96.
Reason(R):For a matrix A of order n and a scalar k, |kA|=kn|A|.
Case Study Questions-
2. The management committee of a residential colony decided to award some of its members (say x) for honesty, some (sayy) for helping others and some others (sayz) for supervising the workers to kept the colony neat and clean. The sum of all the awardees is 12. Three times the sum of awardees for cooperation and supervision added to two times the number of awardees for honesty is 33. The sum of the number of awardees for honesty and supervision is twice the number of awardees for helping.
(i) Value of x + y + z is
(a) 3
(b) 5
(c) 7
(d) 12
(ii) Value of x − 2 y is
(a) z
(b) -z
(c) 2z
(d) -2z
(iii) The value of z is
(a) 3
(b) 4
(c) 5
(d) 6
(iv) The value of x + 2 y is
(a) 9
(b) 10
(c) 11
(d) 12
(v) The value of 2x + 3y + 5z is
(a) 40
(b) 43
(c) 50
(d) 53
Answer Key-
Multiple Choice questions-

Very Short Answer:

Co-factor of a23 = (-1)2 + 3
= (-1)5 (5 x 2 – 1 x 3)
= (-1) (10-3)
= (-1) (7) = -7.
Hence |B| = 3
Given
Hence, (l + m + n) is a factor of given determinant.
| 2 – adj. A| = 23 | A |3-1
= 8(9)2
= 648.
We have: AB = 2I
∴ |AB| = |2I|
⇒ |A||B| = |2I|
⇒ 2|B|= 2(1).
Hence, |B| = 1.
|A. (adj. A) | = |A|n
= 4n or 16 or 64.

(i) a23 =
= (5) (2) – (1) (3)
= 10 – 3 = 7.
(ii) a32 = (-1)3+2
= (-1)5 [(5) (1) – (2) (8)]
= (-1)5 (5 – 16)
= (- 1) (- 11) = 11.
Now A11 = Co-factor of 2 = 3,
A12 = Co-factor of – 1 = – 4,
A21 = Co-factor of 4 = 1
and A22 = Co-factor of 3 = 2
= (2) (7) – (-4) (-3)
= 14 – 12 = 2 ≠ 0.
∴ A-1 exists and
⇒ 4(5 -x) – 2 (x + 1) = 0
⇒ 20 – 4x – 2x – 2 = 0
⇒ 18 – 6x = 0
⇒ 6x = 18.
Hence, x = 3.
Long Answer:
We have
(0 + 9yz) + 3x(3 z + 9yz + 3y)
= 9(3xyz + xy + yz + zx) = RHS
Case Study Answers-
1.
(i) (a) ₹ 2
(ii) (d) ₹ 17
(iii) (a) ₹ 7
(iv) (d) ₹20
(v) (c) ₹22
2.
(i) (d) 12
(ii) (b)-z
(iii) (c)5
(iv) (c) 11
(v) (b)43
Assertion and Reason Answers-
Solution:
Minor of element
∴Given Assertion [A] is false Also we know that minor of an element aijof a matrix is the determinant obtained by deleting its ithrow and jthcolumn.
∴ Given Reason (R) is also false
∴ Both Assertion [A] and Reason [R] are false Hence option (e) is the correct Answer.
2.(b) Both A and R are true but R is not the correct explanation of A.
Solution:
Here,
|2AB|=23|AB|=8|A||B|
=8×3×−4=−96
∴ Assertion [A] is true
{∵|kA|=kn|A|and|AB|=|A||B|}
Also we know that |kA|=kn|A|
for matrix A of order n.
∴ Reason (R) is true But |AB|=|A||B|is not mentioned in Reason R.
∴ Both A and R are true but R is not correct explanation of A Hence option (b) is the correct answer.